Abstract <p>In this paper, a family of block operator matrices <InlineEquation ID="IEq1"> <EquationSource Format="TEX">\({{\mathcal{A}}_{{\text{h}}}}(K),\)</EquationSource> <!--RusMath2670008Rasulov-m1--> </InlineEquation> <InlineEquation ID="IEq2"> <EquationSource Format="TEX">\(K \in {{( - \pi {\text{/h}};\pi {\text{/h}}]}^{3}}\)</EquationSource> <!--RusMath2670008Rasulov-m2--> </InlineEquation>, associated with the Hamiltonian of a system with a non-conserved number of particles not exceeding three on a non-integer lattice <InlineEquation ID="IEq3"> <EquationSource Format="TEX">\({{({\text{h}}\mathbb{Z})}^{3}}\)</EquationSource> <!--RusMath2670008Rasulov-m3--> </InlineEquation> with step <InlineEquation ID="IEq4"> <EquationSource Format="TEX">\({\text{h}} &gt; 0\)</EquationSource> <!--RusMath2670008Rasulov-m4--> </InlineEquation>, is considered. It is established that the operator <InlineEquation ID="IEq5"> <EquationSource Format="TEX">\({{\mathcal{A}}_{{\text{h}}}}({\mathbf{0}}),\)</EquationSource> <!--RusMath2670008Rasulov-m5--> </InlineEquation> <InlineEquation ID="IEq6"> <EquationSource Format="TEX">\({\mathbf{0}}: = (0,0,0),\)</EquationSource> <!--RusMath2670008Rasulov-m6--> </InlineEquation> has a finite number of negative eigenvalues if the corresponding generalized Friedrichs model has a zero eigenvalue. It is shown that the operator <InlineEquation ID="IEq7"> <EquationSource Format="TEX">\({{\mathcal{A}}_{{\text{h}}}}({\mathbf{0}})\)</EquationSource> <!--RusMath2670008Rasulov-m7--> </InlineEquation> possesses an infinite number of negative eigenvalues accumulating at zero (the Efimov effect) if the generalized Friedrichs model has a zero-energy resonance. An asymptotic formula is obtained for the number <InlineEquation ID="IEq8"> <EquationSource Format="TEX">\({{N}_{{\text{h}}}}(z)\)</EquationSource> <!--RusMath2670008Rasulov-m8--> </InlineEquation> of eigenvalues of the operator <InlineEquation ID="IEq9"> <EquationSource Format="TEX">\({{\mathcal{A}}_{{\text{h}}}}({\mathbf{0}})\)</EquationSource> <!--RusMath2670008Rasulov-m9--> </InlineEquation> lying below <InlineEquation ID="IEq10"> <EquationSource Format="TEX">\(z,\)</EquationSource> <!--RusMath2670008Rasulov-m10--> </InlineEquation> <InlineEquation ID="IEq11"> <EquationSource Format="TEX">\(z \leqslant 0\)</EquationSource> <!--RusMath2670008Rasulov-m11--> </InlineEquation> as the spectral parameter <InlineEquation ID="IEq12"> <EquationSource Format="TEX">\(z \to - 0.\)</EquationSource> <!--RusMath2670008Rasulov-m12--> </InlineEquation></p>

错误:搜索内容不能为空,请输入英文关键词
错误:关键词超出字数限制,请精简
高级检索

Investigation of the Number of Negative Eigenvalues of a Third-Order Operator Matrix on a Noninteger Lattice

  • T. H. Rasulov,
  • Sh. B. Nematova

摘要

Abstract

In this paper, a family of block operator matrices \({{\mathcal{A}}_{{\text{h}}}}(K),\) \(K \in {{( - \pi {\text{/h}};\pi {\text{/h}}]}^{3}}\) , associated with the Hamiltonian of a system with a non-conserved number of particles not exceeding three on a non-integer lattice \({{({\text{h}}\mathbb{Z})}^{3}}\) with step \({\text{h}} > 0\) , is considered. It is established that the operator \({{\mathcal{A}}_{{\text{h}}}}({\mathbf{0}}),\) \({\mathbf{0}}: = (0,0,0),\) has a finite number of negative eigenvalues if the corresponding generalized Friedrichs model has a zero eigenvalue. It is shown that the operator \({{\mathcal{A}}_{{\text{h}}}}({\mathbf{0}})\) possesses an infinite number of negative eigenvalues accumulating at zero (the Efimov effect) if the generalized Friedrichs model has a zero-energy resonance. An asymptotic formula is obtained for the number \({{N}_{{\text{h}}}}(z)\) of eigenvalues of the operator \({{\mathcal{A}}_{{\text{h}}}}({\mathbf{0}})\) lying below \(z,\) \(z \leqslant 0\) as the spectral parameter \(z \to - 0.\)