<p>Let <InlineEquation ID="IEq1"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="13370_2025_1266_Article_IEq1.gif" Format="GIF" Height="21" Rendition="HTML" Resolution="72" Type="Linedraw" Width="54" /> </InlineMediaObject> <EquationSource Format="TEX">\(\left( F_n\right) _{n \ge 0}\)</EquationSource> <EquationSource Format="MATHML"><math> <msub> <mfenced close=")" open="("> <msub> <mi>F</mi> <mi>n</mi> </msub> </mfenced> <mrow> <mi>n</mi> <mo>≥</mo> <mn>0</mn> </mrow> </msub> </math></EquationSource> </InlineEquation> and <InlineEquation ID="IEq2"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="13370_2025_1266_Article_IEq2.gif" Format="GIF" Height="21" Rendition="HTML" Resolution="72" Type="Linedraw" Width="60" /> </InlineMediaObject> <EquationSource Format="TEX">\(\left( M_n\right) _{n \ge 0}\)</EquationSource> <EquationSource Format="MATHML"><math> <msub> <mfenced close=")" open="("> <msub> <mi>M</mi> <mi>n</mi> </msub> </mfenced> <mrow> <mi>n</mi> <mo>≥</mo> <mn>0</mn> </mrow> </msub> </math></EquationSource> </InlineEquation> be the Fibonacci and Mulatu sequences. Let <i>b</i> be a positive integer such that <InlineEquation ID="IEq3"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="13370_2025_1266_Article_IEq3.gif" Format="GIF" Height="16" Rendition="HTML" Resolution="72" Type="Linedraw" Width="45" /> </InlineMediaObject> <EquationSource Format="TEX">\(b\ge 2.\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>b</mi> <mo>≥</mo> <mn>2</mn> <mo>.</mo> </mrow> </math></EquationSource> </InlineEquation> In this paper, we prove that the following Diophantine equation <Equation ID="Equ27"> <MediaObject> <ImageObject Color="BlackWhite" FileRef="13370_2025_1266_Article_Equ27.gif" Format="GIF" Height="23" Rendition="HTML" Resolution="72" Type="Linedraw" Width="221" /> </MediaObject> <EquationSource Format="TEX">\(\begin{aligned} F_n+\epsilon M_m=\rho \left( (b\pm 1)b^{\ell }\pm 1\right) , \end{aligned}\)</EquationSource> <EquationSource Format="MATHML"><math display="block"> <mrow> <mtable> <mtr> <mtd columnalign="right"> <mrow> <msub> <mi>F</mi> <mi>n</mi> </msub> <mo>+</mo> <mi>ϵ</mi> <msub> <mi>M</mi> <mi>m</mi> </msub> <mo>=</mo> <mi>ρ</mi> <mfenced close=")" open="("> <mrow> <mo stretchy="false">(</mo> <mi>b</mi> <mo>±</mo> <mn>1</mn> <mo stretchy="false">)</mo> </mrow> <msup> <mi>b</mi> <mi>ℓ</mi> </msup> <mo>±</mo> <mn>1</mn> </mfenced> <mo>,</mo> </mrow> </mtd> </mtr> </mtable> </mrow> </math></EquationSource> </Equation>where <InlineEquation ID="IEq4"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="13370_2025_1266_Article_IEq4.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="240" /> </InlineMediaObject> <EquationSource Format="TEX">\((\epsilon , \rho )\in \{(1, 1), (-1, 1), (-1, -1)\}\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mo stretchy="false">(</mo> <mi>ϵ</mi> <mo>,</mo> <mi>ρ</mi> <mo stretchy="false">)</mo> <mo>∈</mo> <mo stretchy="false">{</mo> <mo stretchy="false">(</mo> <mn>1</mn> <mo>,</mo> <mn>1</mn> <mo stretchy="false">)</mo> <mo>,</mo> <mo stretchy="false">(</mo> <mo>-</mo> <mn>1</mn> <mo>,</mo> <mn>1</mn> <mo stretchy="false">)</mo> <mo>,</mo> <mo stretchy="false">(</mo> <mo>-</mo> <mn>1</mn> <mo>,</mo> <mo>-</mo> <mn>1</mn> <mo stretchy="false">)</mo> <mo stretchy="false">}</mo> </mrow> </math></EquationSource> </InlineEquation> have only finitely many solutions in non-negative integers <i>n</i>,&#xa0; <i>m</i>,&#xa0; <i>b</i> and positive integer <InlineEquation ID="IEq5"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="13370_2025_1266_Article_IEq5.gif" Format="GIF" Height="14" Rendition="HTML" Resolution="72" Type="Linedraw" Width="14" /> </InlineMediaObject> <EquationSource Format="TEX">\(\ell .\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>ℓ</mi> <mo>.</mo> </mrow> </math></EquationSource> </InlineEquation> Additionally, we present a method to determine all solutions within the range <InlineEquation ID="IEq6"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="13370_2025_1266_Article_IEq6.gif" Format="GIF" Height="16" Rendition="HTML" Resolution="72" Type="Linedraw" Width="84" /> </InlineMediaObject> <EquationSource Format="TEX">\(2 \le b \le 12.\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mn>2</mn> <mo>≤</mo> <mi>b</mi> <mo>≤</mo> <mn>12</mn> <mo>.</mo> </mrow> </math></EquationSource> </InlineEquation> All this is done using linear forms in logarithms of algebraic numbers and Dujella–Pethő’s reduction method.</p>

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On Thabit and Williams numbers base b as sum or difference of Fibonacci and Mulatu numbers and vice versa

  • Kouèssi Norbert Adédji,
  • Mohamadou Bachabi,
  • Alain Togbé

摘要

Let \(\left( F_n\right) _{n \ge 0}\) F n n 0 and \(\left( M_n\right) _{n \ge 0}\) M n n 0 be the Fibonacci and Mulatu sequences. Let b be a positive integer such that \(b\ge 2.\) b 2 . In this paper, we prove that the following Diophantine equation \(\begin{aligned} F_n+\epsilon M_m=\rho \left( (b\pm 1)b^{\ell }\pm 1\right) , \end{aligned}\) F n + ϵ M m = ρ ( b ± 1 ) b ± 1 , where \((\epsilon , \rho )\in \{(1, 1), (-1, 1), (-1, -1)\}\) ( ϵ , ρ ) { ( 1 , 1 ) , ( - 1 , 1 ) , ( - 1 , - 1 ) } have only finitely many solutions in non-negative integers nmb and positive integer \(\ell .\) . Additionally, we present a method to determine all solutions within the range \(2 \le b \le 12.\) 2 b 12 . All this is done using linear forms in logarithms of algebraic numbers and Dujella–Pethő’s reduction method.