<p>We develop a new proof of the result of L.-E.&#xa0;Persson and V.D.&#xa0;Stepanov [<CitationRef CitationID="CR24">24</CitationRef>, Theorems 1 and 3], which provides a characterization of a Hardy integral inequality involving two weights, and which can be applied to an effective treatment of the geometric mean operator. Our approach enables us to extend their result to the full range of parameters, in particular involving the critical case <InlineEquation ID="IEq1"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="13324_2025_1102_Article_IEq1.gif" Format="GIF" Height="16" Rendition="HTML" Resolution="72" Type="Linedraw" Width="41" /> </InlineMediaObject> <EquationSource Format="TEX">\(p=1\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>p</mi> <mo>=</mo> <mn>1</mn> </mrow> </math></EquationSource> </InlineEquation>, which was excluded in the original work. Our proof avoids all duality steps and discretization techniques and uses solely elementary means.</p>

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The Persson–Stepanov theorem revisited

  • Amiran Gogatishvili,
  • Luboš Pick,
  • Hana Turčinová,
  • Tuğçe Ünver

摘要

We develop a new proof of the result of L.-E. Persson and V.D. Stepanov [24, Theorems 1 and 3], which provides a characterization of a Hardy integral inequality involving two weights, and which can be applied to an effective treatment of the geometric mean operator. Our approach enables us to extend their result to the full range of parameters, in particular involving the critical case \(p=1\) p = 1 , which was excluded in the original work. Our proof avoids all duality steps and discretization techniques and uses solely elementary means.