<p>In this note, we demonstrate that <InlineEquation ID="IEq2"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="12045_2025_1748_Article_IEq2.gif" Format="GIF" Height="21" Rendition="HTML" Resolution="72" Type="Linedraw" Width="79" /> </InlineMediaObject> <EquationSource Format="TEX">\(\pi^{e^{e^{\pi}}} &lt; e^{\pi^{\pi^{e}}}\)</EquationSource> <EquationSource Format="MATHML"><math display="block"> <msup> <mi>π</mi> <mrow> <msup> <mi>e</mi> <mrow> <msup> <mi>e</mi> <mrow> <mi>π</mi> </mrow> </msup> </mrow> </msup> </mrow> </msup> <mo>&lt;</mo> <msup> <mi>e</mi> <mrow> <msup> <mi>π</mi> <mrow> <msup> <mi>π</mi> <mrow> <mi>e</mi> </mrow> </msup> </mrow> </msup> </mrow> </msup> </math></EquationSource> </InlineEquation>. This resolves an open question posed by Pinter (2005) in <i>The Mathematical Gazette</i>. This note presents a concise solution that does not rely on any computational tools.</p>

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A Proof that \(\pi^{e^{e^{\pi}}} < e^{\pi^{\pi^{e}}}\)

  • Brahim Chaourar,
  • Lazhar Bougoffa

摘要

In this note, we demonstrate that \(\pi^{e^{e^{\pi}}} < e^{\pi^{\pi^{e}}}\) π e e π < e π π e . This resolves an open question posed by Pinter (2005) in The Mathematical Gazette. This note presents a concise solution that does not rely on any computational tools.