<p>The <i>k</i>-partite entanglement, which focus on at most how many particles in the global system are entangled but separable from other particles, is complementary to the <i>k</i>-entanglement that reflects how many split subsystems are entangled under partitions of the systems in characterizing multipartite entanglement. Very recently, the theory of the complete <i>k</i>-entanglement measure has been established in [Phys. Rev. A 110, 012405 (2024)]. Here we investigate whether we can define the complete measure of the <i>k</i>-partite entanglement. Consequently, with the same spirit as that of the complete <i>k</i>-entanglement measure, we present the axiomatic postulates that a complete <i>k</i>-partite entanglement measure should require. Furthermore, we present two classes of <i>k</i>-partite entanglement measures and show that one is complete while the other one is unified but not complete except for the case of <InlineEquation ID="IEq1"> <EquationSource Format="TEX">\(k=2\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>k</mi> <mo>=</mo> <mn>2</mn> </mrow> </math></EquationSource> </InlineEquation>.</p>

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Complete k-partite entanglement measure

  • Jinxing Zhao,
  • Yu Guo,
  • Fei He

摘要

The k-partite entanglement, which focus on at most how many particles in the global system are entangled but separable from other particles, is complementary to the k-entanglement that reflects how many split subsystems are entangled under partitions of the systems in characterizing multipartite entanglement. Very recently, the theory of the complete k-entanglement measure has been established in [Phys. Rev. A 110, 012405 (2024)]. Here we investigate whether we can define the complete measure of the k-partite entanglement. Consequently, with the same spirit as that of the complete k-entanglement measure, we present the axiomatic postulates that a complete k-partite entanglement measure should require. Furthermore, we present two classes of k-partite entanglement measures and show that one is complete while the other one is unified but not complete except for the case of \(k=2\) k = 2 .