<p>Let <InlineEquation ID="IEq1"> <EquationSource Format="TEX">\(\mu _2\)</EquationSource> <EquationSource Format="MATHML"><math> <msub> <mi>μ</mi> <mn>2</mn> </msub> </math></EquationSource> </InlineEquation> be the characteristic function of the square free integers and let [<i>t</i>] be the integral part of real number <i>t</i>. In this paper, we prove that for any <InlineEquation ID="IEq2"> <EquationSource Format="TEX">\(\varepsilon &gt;0\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>ε</mi> <mo>&gt;</mo> <mn>0</mn> </mrow> </math></EquationSource> </InlineEquation> the asymptotic formulas <Equation ID="Equ26"> <EquationSource Format="TEX">\( \sum _{n\leqslant x} \mu _2\Big (\Big [\frac{x}{n}\Big ]\Big ) = \sum _{d=1}^{\infty } \frac{\mu _2(d)}{d(d+1)} x + O_{\varepsilon }(x^{3/8+\varepsilon }) \)</EquationSource> <EquationSource Format="MATHML"><math display="block"> <mrow> <munder> <mo>∑</mo> <mrow> <mi>n</mi> <mo>⩽</mo> <mi>x</mi> </mrow> </munder> <msub> <mi>μ</mi> <mn>2</mn> </msub> <mrow> <mo maxsize="1.623em" minsize="1.623em" stretchy="true">(</mo> </mrow> <mrow> <mo maxsize="1.623em" minsize="1.623em" stretchy="true">[</mo> </mrow> <mfrac> <mi>x</mi> <mi>n</mi> </mfrac> <mrow> <mo maxsize="1.623em" minsize="1.623em" stretchy="true">]</mo> </mrow> <mrow> <mo maxsize="1.623em" minsize="1.623em" stretchy="true">)</mo> </mrow> <mo>=</mo> <munderover> <mo>∑</mo> <mrow> <mi>d</mi> <mo>=</mo> <mn>1</mn> </mrow> <mi>∞</mi> </munderover> <mfrac> <mrow> <msub> <mi>μ</mi> <mn>2</mn> </msub> <mrow> <mo stretchy="false">(</mo> <mi>d</mi> <mo stretchy="false">)</mo> </mrow> </mrow> <mrow> <mi>d</mi> <mo stretchy="false">(</mo> <mi>d</mi> <mo>+</mo> <mn>1</mn> <mo stretchy="false">)</mo> </mrow> </mfrac> <mi>x</mi> <mo>+</mo> <msub> <mi>O</mi> <mi>ε</mi> </msub> <mrow> <mo stretchy="false">(</mo> <msup> <mi>x</mi> <mrow> <mn>3</mn> <mo stretchy="false">/</mo> <mn>8</mn> <mo>+</mo> <mi>ε</mi> </mrow> </msup> <mo stretchy="false">)</mo> </mrow> </mrow> </math></EquationSource> </Equation>holds for <InlineEquation ID="IEq3"> <EquationSource Format="TEX">\(x\rightarrow \infty \)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>x</mi> <mo stretchy="false">→</mo> <mi>∞</mi> </mrow> </math></EquationSource> </InlineEquation>. This improves the corresponding result of Zhang, which requires <InlineEquation ID="IEq4"> <EquationSource Format="TEX">\(\frac{11}{29}\)</EquationSource> <EquationSource Format="MATHML"><math> <mfrac> <mn>11</mn> <mn>29</mn> </mfrac> </math></EquationSource> </InlineEquation> in place of <InlineEquation ID="IEq5"> <EquationSource Format="TEX">\(\frac{3}{8}\)</EquationSource> <EquationSource Format="MATHML"><math> <mfrac> <mn>3</mn> <mn>8</mn> </mfrac> </math></EquationSource> </InlineEquation>. We also establish asymptotic formula <Equation ID="Equ27"> <EquationSource Format="TEX">\( \sum _{\begin{array}{c} d\leqslant x\\ \exists \,n\;\text {such that}\;[\frac{x}{n}]=d \end{array}} \mu _2(d) = \frac{12}{\pi ^2} \sqrt{x} + O_{\varepsilon }(x^{3/8+\varepsilon }). \)</EquationSource> <EquationSource Format="MATHML"><math display="block"> <mrow> <munder> <mo>∑</mo> <mrow> <mtable> <mtr> <mtd> <mrow> <mi>d</mi> <mo>⩽</mo> <mi>x</mi> </mrow> </mtd> </mtr> <mtr> <mtd> <mrow> <mrow /> <mo>∃</mo> <mspace width="0.166667em" /> <mi>n</mi> <mspace width="0.277778em" /> <mtext>such that</mtext> <mspace width="0.277778em" /> <mo stretchy="false">[</mo> <mfrac> <mi>x</mi> <mi>n</mi> </mfrac> <mo stretchy="false">]</mo> <mo>=</mo> <mi>d</mi> </mrow> </mtd> </mtr> </mtable> </mrow> </munder> <msub> <mi>μ</mi> <mn>2</mn> </msub> <mrow> <mo stretchy="false">(</mo> <mi>d</mi> <mo stretchy="false">)</mo> </mrow> <mo>=</mo> <mfrac> <mn>12</mn> <msup> <mi>π</mi> <mn>2</mn> </msup> </mfrac> <msqrt> <mi>x</mi> </msqrt> <mo>+</mo> <msub> <mi>O</mi> <mi>ε</mi> </msub> <mrow> <mo stretchy="false">(</mo> <msup> <mi>x</mi> <mrow> <mn>3</mn> <mo stretchy="false">/</mo> <mn>8</mn> <mo>+</mo> <mi>ε</mi> </mrow> </msup> <mo stretchy="false">)</mo> </mrow> <mo>.</mo> </mrow> </math></EquationSource> </Equation></p>

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Distribution of square free integers involving the floor function

  • Jiayuan Hu,
  • Jie Wu

摘要

Let \(\mu _2\) μ 2 be the characteristic function of the square free integers and let [t] be the integral part of real number t. In this paper, we prove that for any \(\varepsilon >0\) ε > 0 the asymptotic formulas \( \sum _{n\leqslant x} \mu _2\Big (\Big [\frac{x}{n}\Big ]\Big ) = \sum _{d=1}^{\infty } \frac{\mu _2(d)}{d(d+1)} x + O_{\varepsilon }(x^{3/8+\varepsilon }) \) n x μ 2 ( [ x n ] ) = d = 1 μ 2 ( d ) d ( d + 1 ) x + O ε ( x 3 / 8 + ε ) holds for \(x\rightarrow \infty \) x . This improves the corresponding result of Zhang, which requires \(\frac{11}{29}\) 11 29 in place of \(\frac{3}{8}\) 3 8 . We also establish asymptotic formula \( \sum _{\begin{array}{c} d\leqslant x\\ \exists \,n\;\text {such that}\;[\frac{x}{n}]=d \end{array}} \mu _2(d) = \frac{12}{\pi ^2} \sqrt{x} + O_{\varepsilon }(x^{3/8+\varepsilon }). \) d x n such that [ x n ] = d μ 2 ( d ) = 12 π 2 x + O ε ( x 3 / 8 + ε ) .