<p>Computational and experimental studies have been made of obtaining hydrogen fluoride from uranium hexafluoride during its interaction with methane and oxygen in a combustion regime. The calculations have shown that in a thermodynamically equilibrium mixture in the system of elements U-F-C-H-O in which the number of hydrogen atoms is larger than or equal to the number of fluoride atoms, and the number of oxygen atoms is twice as large as the number of uranium atoms, the fluoride-containing substance at a temperature higher than 1100 K is hydrogen fluoride, and the basic uranium-containing substances are uranium oxides. Uranium fluorides and uranium oxyfluorides amount to about 3% of the mixture, and there are no carbon fluorides and oxyfluorides in it. A required temperature of the mixture may be attained during the interaction of uranium hexafluoride with methane and oxygen in a combustion regime. It has been established experimentally that in a reactor of the tunnel-burner type of diameter 142 mm in the UF₆-CH₄-O₂ mixture with a nearly 1.0:1.5:2.5 mole ratio of the substances, the flame is reliably formed using the self-igniting F₂–NH₃ pair and is stably burning at a rate of flow of uranium hexafluoride of the order of units of grams a second. The basic uranium-containing product of the process of combustion is a mixture of uranium oxides UO₂ and U₃O₈, in which covalent-bonded fluorine is present in the amount of about 1% mainly in the form of UF₄, and the basic fluorine-containing product is hydrofluoric acid with a content of hydrogen fluoride higher than 95%.</p>