<p>For a fixed graph <i>F</i>, a graph <i>G</i> is <i>F</i>-saturated if <i>G</i> does not contain <i>F</i> as a subgraph, but adding any edge in <InlineEquation ID="IEq3"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="10878_2024_1256_Article_IEq3.gif" Format="GIF" Height="20" Rendition="HTML" Resolution="72" Type="Linedraw" Width="41" /> </InlineMediaObject> <EquationSource Format="TEX">\(E(\overline{G})\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>E</mi> <mo stretchy="false">(</mo> <mover> <mi>G</mi> <mo>¯</mo> </mover> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation> will result in a copy of <i>F</i>. The minimum size of an <i>F</i>-saturated graph of order <i>n</i> is called the saturation number of <i>F</i>, denoted by <i>sat</i>(<i>n</i>,&#xa0;<i>F</i>). In this paper, we are interested in saturation problem of graph <InlineEquation ID="IEq4"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="10878_2024_1256_Article_IEq4.gif" Format="GIF" Height="16" Rendition="HTML" Resolution="72" Type="Linedraw" Width="58" /> </InlineMediaObject> <EquationSource Format="TEX">\(K_1\vee {P_t}\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <msub> <mi>K</mi> <mn>1</mn> </msub> <mo>∨</mo> <msub> <mi>P</mi> <mi>t</mi> </msub> </mrow> </math></EquationSource> </InlineEquation> for <InlineEquation ID="IEq5"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="10878_2024_1256_Article_IEq5.gif" Format="GIF" Height="15" Rendition="HTML" Resolution="72" Type="Linedraw" Width="39" /> </InlineMediaObject> <EquationSource Format="TEX">\(t\ge 2\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>t</mi> <mo>≥</mo> <mn>2</mn> </mrow> </math></EquationSource> </InlineEquation>. As some known results, <InlineEquation ID="IEq6"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="10878_2024_1256_Article_IEq6.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="110" /> </InlineMediaObject> <EquationSource Format="TEX">\(sat(n,K_1\vee {P_t})\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>s</mi> <mi>a</mi> <mi>t</mi> <mo stretchy="false">(</mo> <mi>n</mi> <mo>,</mo> <msub> <mi>K</mi> <mn>1</mn> </msub> <mo>∨</mo> <msub> <mi>P</mi> <mi>t</mi> </msub> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation> is determined for <InlineEquation ID="IEq7"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="10878_2024_1256_Article_IEq7.gif" Format="GIF" Height="15" Rendition="HTML" Resolution="72" Type="Linedraw" Width="70" /> </InlineMediaObject> <EquationSource Format="TEX">\(2\le t\le 4\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mn>2</mn> <mo>≤</mo> <mi>t</mi> <mo>≤</mo> <mn>4</mn> </mrow> </math></EquationSource> </InlineEquation>. We will show that <InlineEquation ID="IEq8"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="10878_2024_1256_Article_IEq8.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="300" /> </InlineMediaObject> <EquationSource Format="TEX">\(sat(n,K_1\vee {P_t})=(n-1)+sat(n-1,P_t)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>s</mi> <mi>a</mi> <mi>t</mi> <mrow> <mo stretchy="false">(</mo> <mi>n</mi> <mo>,</mo> <msub> <mi>K</mi> <mn>1</mn> </msub> <mo>∨</mo> <msub> <mi>P</mi> <mi>t</mi> </msub> <mo stretchy="false">)</mo> </mrow> <mo>=</mo> <mrow> <mo stretchy="false">(</mo> <mi>n</mi> <mo>-</mo> <mn>1</mn> <mo stretchy="false">)</mo> </mrow> <mo>+</mo> <mi>s</mi> <mi>a</mi> <mi>t</mi> <mrow> <mo stretchy="false">(</mo> <mi>n</mi> <mo>-</mo> <mn>1</mn> <mo>,</mo> <msub> <mi>P</mi> <mi>t</mi> </msub> <mo stretchy="false">)</mo> </mrow> </mrow> </math></EquationSource> </InlineEquation> for <InlineEquation ID="IEq9"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="10878_2024_1256_Article_IEq9.gif" Format="GIF" Height="15" Rendition="HTML" Resolution="72" Type="Linedraw" Width="39" /> </InlineMediaObject> <EquationSource Format="TEX">\(t\ge 5\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>t</mi> <mo>≥</mo> <mn>5</mn> </mrow> </math></EquationSource> </InlineEquation> and <i>n</i> sufficiently large. Moreover, <InlineEquation ID="IEq10"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="10878_2024_1256_Article_IEq10.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="69" /> </InlineMediaObject> <EquationSource Format="TEX">\((K_1\vee {P_t})\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mo stretchy="false">(</mo> <msub> <mi>K</mi> <mn>1</mn> </msub> <mo>∨</mo> <msub> <mi>P</mi> <mi>t</mi> </msub> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation>-saturated graphs with <InlineEquation ID="IEq11"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="10878_2024_1256_Article_IEq11.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="110" /> </InlineMediaObject> <EquationSource Format="TEX">\(sat(n,K_1\vee {P_t})\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>s</mi> <mi>a</mi> <mi>t</mi> <mo stretchy="false">(</mo> <mi>n</mi> <mo>,</mo> <msub> <mi>K</mi> <mn>1</mn> </msub> <mo>∨</mo> <msub> <mi>P</mi> <mi>t</mi> </msub> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation> edges are characterized.</p>

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\((K_{1}\vee {P_{t})}\)-saturated graphs with minimum number of edges

  • Jinze Hu,
  • Shengjin Ji,
  • Qing Cui

摘要

For a fixed graph F, a graph G is F-saturated if G does not contain F as a subgraph, but adding any edge in \(E(\overline{G})\) E ( G ¯ ) will result in a copy of F. The minimum size of an F-saturated graph of order n is called the saturation number of F, denoted by sat(nF). In this paper, we are interested in saturation problem of graph \(K_1\vee {P_t}\) K 1 P t for \(t\ge 2\) t 2 . As some known results, \(sat(n,K_1\vee {P_t})\) s a t ( n , K 1 P t ) is determined for \(2\le t\le 4\) 2 t 4 . We will show that \(sat(n,K_1\vee {P_t})=(n-1)+sat(n-1,P_t)\) s a t ( n , K 1 P t ) = ( n - 1 ) + s a t ( n - 1 , P t ) for \(t\ge 5\) t 5 and n sufficiently large. Moreover, \((K_1\vee {P_t})\) ( K 1 P t ) -saturated graphs with \(sat(n,K_1\vee {P_t})\) s a t ( n , K 1 P t ) edges are characterized.