<p>Given a functor <InlineEquation ID="IEq1"> <EquationSource Format="TEX">\(F: \mathcal {C}\rightarrow \mathcal {D}\)</EquationSource> </InlineEquation> and a model-theoretic independence relation on <InlineEquation ID="IEq2"> <EquationSource Format="TEX">\(\mathcal {D}\)</EquationSource> </InlineEquation>, we can lift that independence relation along <i>F</i> to <InlineEquation ID="IEq3"> <EquationSource Format="TEX">\(\mathcal {C}\)</EquationSource> </InlineEquation> by declaring a commuting square in <InlineEquation ID="IEq4"> <EquationSource Format="TEX">\(\mathcal {C}\)</EquationSource> </InlineEquation> to be independent if its image under <i>F</i> is independent. For each property of interest that an independence relation can have we give assumptions on the functor that guarantee the property to be lifted.</p>

错误:搜索内容不能为空,请输入英文关键词
错误:关键词超出字数限制,请精简
高级检索

Lifting Independence Along Functors

  • M. Kamsma,
  • J. Rosický

摘要

Given a functor \(F: \mathcal {C}\rightarrow \mathcal {D}\) and a model-theoretic independence relation on \(\mathcal {D}\) , we can lift that independence relation along F to \(\mathcal {C}\) by declaring a commuting square in \(\mathcal {C}\) to be independent if its image under F is independent. For each property of interest that an independence relation can have we give assumptions on the functor that guarantee the property to be lifted.