<p>We consider the conditional Jensen functional equation<Equation ID="Equa"> <MediaObject> <ImageObject Color="BlackWhite" FileRef="10474_2025_1527_Article_Equa.gif" Format="GIF" Height="35" Rendition="HTML" Resolution="72" Type="Linedraw" Width="403" /> </MediaObject> <EquationSource Format="TEX">\(f(x+y)\ne 0 \implies 2f\big(\frac{x+y}{2}\big)=f(x)+f(y), \quad x,y\in \mathcal{G}\)</EquationSource> <EquationSource Format="MATHML"><math display="block"> <mrow> <mi>f</mi> <mrow> <mo stretchy="false">(</mo> <mi>x</mi> <mo>+</mo> <mi>y</mi> <mo stretchy="false">)</mo> </mrow> <mo>≠</mo> <mn>0</mn> <mo stretchy="false">⇒</mo> <mn>2</mn> <mi>f</mi> <mrow> <mo maxsize="1.2em" minsize="1.2em" stretchy="true">(</mo> </mrow> <mfrac> <mrow> <mi>x</mi> <mo>+</mo> <mi>y</mi> </mrow> <mn>2</mn> </mfrac> <mrow> <mo maxsize="1.2em" minsize="1.2em" stretchy="true">)</mo> </mrow> <mo>=</mo> <mi>f</mi> <mrow> <mo stretchy="false">(</mo> <mi>x</mi> <mo stretchy="false">)</mo> </mrow> <mo>+</mo> <mi>f</mi> <mrow> <mo stretchy="false">(</mo> <mi>y</mi> <mo stretchy="false">)</mo> </mrow> <mo>,</mo> <mspace width="1em" /> <mi>x</mi> <mo>,</mo> <mi>y</mi> <mo>∈</mo> <mi mathvariant="script">G</mi> </mrow> </math></EquationSource> </Equation>for functions <InlineEquation ID="IEq2"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="10474_2025_1527_Article_IEq2.gif" Format="GIF" Height="17" Rendition="HTML" Resolution="72" Type="Linedraw" Width="76" /> </InlineMediaObject> <EquationSource Format="TEX">\(f \colon \mathcal{G} \to\mathcal{V}\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>f</mi> <mo lspace="0pt">:</mo> <mi mathvariant="script">G</mi> <mo stretchy="false">→</mo> <mi mathvariant="script">V</mi> </mrow> </math></EquationSource> </InlineEquation>, where <InlineEquation ID="IEq3"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="10474_2025_1527_Article_IEq3.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="45" /> </InlineMediaObject> <EquationSource Format="TEX">\((\mathcal{G},+)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mo stretchy="false">(</mo> <mi mathvariant="script">G</mi> <mo>,</mo> <mo>+</mo> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation> and <InlineEquation ID="IEq4"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="10474_2025_1527_Article_IEq4.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="46" /> </InlineMediaObject> <EquationSource Format="TEX">\((\mathcal{V},+)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mo stretchy="false">(</mo> <mi mathvariant="script">V</mi> <mo>,</mo> <mo>+</mo> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation> are uniquely 2-divisible groups,with <InlineEquation ID="IEq5"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="10474_2025_1527_Article_IEq4.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="46" /> </InlineMediaObject> <EquationSource Format="TEX">\((\mathcal{V},+)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mo stretchy="false">(</mo> <mi mathvariant="script">V</mi> <mo>,</mo> <mo>+</mo> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation> being abelian. Additionally, we investigate the hyperstability of thisfunctional equation.</p>

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On Jensen-like form of Mikusiński's functional equation

  • E. Imani,
  • A. Najati,
  • M. A. Tareeghee

摘要

We consider the conditional Jensen functional equation \(f(x+y)\ne 0 \implies 2f\big(\frac{x+y}{2}\big)=f(x)+f(y), \quad x,y\in \mathcal{G}\) f ( x + y ) 0 2 f ( x + y 2 ) = f ( x ) + f ( y ) , x , y G for functions \(f \colon \mathcal{G} \to\mathcal{V}\) f : G V , where \((\mathcal{G},+)\) ( G , + ) and \((\mathcal{V},+)\) ( V , + ) are uniquely 2-divisible groups,with \((\mathcal{V},+)\) ( V , + ) being abelian. Additionally, we investigate the hyperstability of thisfunctional equation.