<p>In this paper, we investigate the quasilinear problem given by the following equation in <InlineEquation ID="IEq1"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="25_2025_2530_Article_IEq1.gif" Format="GIF" Height="17" Rendition="HTML" Resolution="72" Type="Linedraw" Width="23" /> </InlineMediaObject> <EquationSource Format="TEX">\(\mathbb {R}^{N}\)</EquationSource> <EquationSource Format="MATHML"><math> <msup> <mrow> <mi mathvariant="double-struck">R</mi> </mrow> <mi>N</mi> </msup> </math></EquationSource> </InlineEquation>: <Equation ID="Equ44"> <MediaObject> <ImageObject Color="BlackWhite" FileRef="25_2025_2530_Article_Equ44.gif" Format="GIF" Height="49" Rendition="HTML" Resolution="72" Type="Linedraw" Width="390" /> </MediaObject> <EquationSource Format="TEX">\(\begin{aligned}&amp;-\text{ div }\left( |x|^{-ap}|\nabla u|^{p-2}\nabla u\right) +|x|^{-bp^{*}}[1+\mu V(z)]|u|^{p-2}u\\ &amp;\quad = |x|^{-bp^{*}}f(u)+|x|^{-bp^{*}}\varrho |u|^{\sigma -2}u. \end{aligned}\)</EquationSource> <EquationSource Format="MATHML"><math display="block"> <mrow> <mtable> <mtr> <mtd /> <mtd columnalign="left"> <mrow> <mo>-</mo> <mspace width="0.333333em" /> <mtext>div</mtext> <mspace width="0.333333em" /> <mfenced close=")" open="("> <msup> <mrow> <mo stretchy="false">|</mo> <mi>x</mi> <mo stretchy="false">|</mo> </mrow> <mrow> <mo>-</mo> <mi>a</mi> <mi>p</mi> </mrow> </msup> <msup> <mrow> <mo stretchy="false">|</mo> <mi mathvariant="normal">∇</mi> <mi>u</mi> <mo stretchy="false">|</mo> </mrow> <mrow> <mi>p</mi> <mo>-</mo> <mn>2</mn> </mrow> </msup> <mi mathvariant="normal">∇</mi> <mi>u</mi> </mfenced> <mo>+</mo> <mmultiscripts> <mrow> <mo stretchy="false">|</mo> <mi>x</mi> <mo stretchy="false">|</mo> </mrow> <mrow /> <mrow> <mo>-</mo> <mi>b</mi> <mmultiscripts> <mi>p</mi> <mrow /> <mrow> <mrow /> <mo>∗</mo> </mrow> </mmultiscripts> </mrow> </mmultiscripts> <mrow> <mo stretchy="false">[</mo> <mn>1</mn> <mo>+</mo> <mi>μ</mi> <mi>V</mi> <mrow> <mo stretchy="false">(</mo> <mi>z</mi> <mo stretchy="false">)</mo> </mrow> <mo stretchy="false">]</mo> </mrow> <msup> <mrow> <mo stretchy="false">|</mo> <mi>u</mi> <mo stretchy="false">|</mo> </mrow> <mrow> <mi>p</mi> <mo>-</mo> <mn>2</mn> </mrow> </msup> <mi>u</mi> </mrow> </mtd> </mtr> <mtr> <mtd columnalign="right"> <mrow /> </mtd> <mtd columnalign="left"> <mrow> <mspace width="1em" /> <mo>=</mo> <mmultiscripts> <mrow> <mo stretchy="false">|</mo> <mi>x</mi> <mo stretchy="false">|</mo> </mrow> <mrow /> <mrow> <mo>-</mo> <mi>b</mi> <mmultiscripts> <mi>p</mi> <mrow /> <mrow> <mrow /> <mo>∗</mo> </mrow> </mmultiscripts> </mrow> </mmultiscripts> <mi>f</mi> <mrow> <mo stretchy="false">(</mo> <mi>u</mi> <mo stretchy="false">)</mo> </mrow> <mo>+</mo> <mmultiscripts> <mrow> <mo stretchy="false">|</mo> <mi>x</mi> <mo stretchy="false">|</mo> </mrow> <mrow /> <mrow> <mo>-</mo> <mi>b</mi> <mmultiscripts> <mi>p</mi> <mrow /> <mrow> <mrow /> <mo>∗</mo> </mrow> </mmultiscripts> </mrow> </mmultiscripts> <mi>ϱ</mi> <msup> <mrow> <mo stretchy="false">|</mo> <mi>u</mi> <mo stretchy="false">|</mo> </mrow> <mrow> <mi>σ</mi> <mo>-</mo> <mn>2</mn> </mrow> </msup> <mi>u</mi> <mo>.</mo> </mrow> </mtd> </mtr> </mtable> </mrow> </math></EquationSource> </Equation>Here, <InlineEquation ID="IEq2"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="25_2025_2530_Article_IEq2.gif" Format="GIF" Height="17" Rendition="HTML" Resolution="72" Type="Linedraw" Width="80" /> </InlineMediaObject> <EquationSource Format="TEX">\(1&lt;p&lt;N\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mn>1</mn> <mo>&lt;</mo> <mi>p</mi> <mo>&lt;</mo> <mi>N</mi> </mrow> </math></EquationSource> </InlineEquation>, <InlineEquation ID="IEq3"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="25_2025_2530_Article_IEq3.gif" Format="GIF" Height="26" Rendition="HTML" Resolution="72" Type="Linedraw" Width="92" /> </InlineMediaObject> <EquationSource Format="TEX">\(0\le a&lt; \frac{N-p}{p}\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mn>0</mn> <mo>≤</mo> <mi>a</mi> <mo>&lt;</mo> <mfrac> <mrow> <mi>N</mi> <mo>-</mo> <mi>p</mi> </mrow> <mi>p</mi> </mfrac> </mrow> </math></EquationSource> </InlineEquation>, <InlineEquation ID="IEq4"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="25_2025_2530_Article_IEq4.gif" Format="GIF" Height="16" Rendition="HTML" Resolution="72" Type="Linedraw" Width="100" /> </InlineMediaObject> <EquationSource Format="TEX">\(a&lt;b\le a+1\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>a</mi> <mo>&lt;</mo> <mi>b</mi> <mo>≤</mo> <mi>a</mi> <mo>+</mo> <mn>1</mn> </mrow> </math></EquationSource> </InlineEquation>, <InlineEquation ID="IEq5"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="25_2025_2530_Article_IEq5.gif" Format="GIF" Height="26" Rendition="HTML" Resolution="72" Type="Linedraw" Width="134" /> </InlineMediaObject> <EquationSource Format="TEX">\(p=p(a,b)=\frac{pN}{N-dp}\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>p</mi> <mo>=</mo> <mi>p</mi> <mrow> <mo stretchy="false">(</mo> <mi>a</mi> <mo>,</mo> <mi>b</mi> <mo stretchy="false">)</mo> </mrow> <mo>=</mo> <mfrac> <mrow> <mi mathvariant="italic">pN</mi> </mrow> <mrow> <mi>N</mi> <mo>-</mo> <mi>d</mi> <mi>p</mi> </mrow> </mfrac> </mrow> </math></EquationSource> </InlineEquation> and <InlineEquation ID="IEq6"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="25_2025_2530_Article_IEq6.gif" Format="GIF" Height="15" Rendition="HTML" Resolution="72" Type="Linedraw" Width="100" /> </InlineMediaObject> <EquationSource Format="TEX">\(d=1+a-b\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>d</mi> <mo>=</mo> <mn>1</mn> <mo>+</mo> <mi>a</mi> <mo>-</mo> <mi>b</mi> </mrow> </math></EquationSource> </InlineEquation>. This equation exhibits singularity not only in the nonlinearity but also in the operator. By imposing suitable assumptions on the functions <i>V</i> and <i>f</i>, we establish the existence of solutions and investigate their concentration behavior as <InlineEquation ID="IEq7"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="25_2025_2530_Article_IEq7.gif" Format="GIF" Height="15" Rendition="HTML" Resolution="72" Type="Linedraw" Width="71" /> </InlineMediaObject> <EquationSource Format="TEX">\(\mu \rightarrow +\infty \)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>μ</mi> <mo stretchy="false">→</mo> <mo>+</mo> <mi>∞</mi> </mrow> </math></EquationSource> </InlineEquation>. We consider three cases: the subcritical case, the critical case, and the supercritical case. In the subcritical case, we have <InlineEquation ID="IEq8"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="25_2025_2530_Article_IEq8.gif" Format="GIF" Height="16" Rendition="HTML" Resolution="72" Type="Linedraw" Width="41" /> </InlineMediaObject> <EquationSource Format="TEX">\(\varrho =0\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>ϱ</mi> <mo>=</mo> <mn>0</mn> </mrow> </math></EquationSource> </InlineEquation>, while in the critical case, we have <InlineEquation ID="IEq9"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="25_2025_2530_Article_IEq9.gif" Format="GIF" Height="16" Rendition="HTML" Resolution="72" Type="Linedraw" Width="41" /> </InlineMediaObject> <EquationSource Format="TEX">\(\varrho =1\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>ϱ</mi> <mo>=</mo> <mn>1</mn> </mrow> </math></EquationSource> </InlineEquation> and <InlineEquation ID="IEq10"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="25_2025_2530_Article_IEq10.gif" Format="GIF" Height="17" Rendition="HTML" Resolution="72" Type="Linedraw" Width="50" /> </InlineMediaObject> <EquationSource Format="TEX">\(\sigma =p^{*}\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>σ</mi> <mo>=</mo> <mmultiscripts> <mi>p</mi> <mrow /> <mrow> <mrow /> <mo>∗</mo> </mrow> </mmultiscripts> </mrow> </math></EquationSource> </InlineEquation>. In the supercritical case, we have <InlineEquation ID="IEq11"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="25_2025_2530_Article_IEq9.gif" Format="GIF" Height="16" Rendition="HTML" Resolution="72" Type="Linedraw" Width="41" /> </InlineMediaObject> <EquationSource Format="TEX">\(\varrho =1\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>ϱ</mi> <mo>=</mo> <mn>1</mn> </mrow> </math></EquationSource> </InlineEquation> and <InlineEquation ID="IEq12"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="25_2025_2530_Article_IEq12.gif" Format="GIF" Height="17" Rendition="HTML" Resolution="72" Type="Linedraw" Width="50" /> </InlineMediaObject> <EquationSource Format="TEX">\(\sigma &gt;p^{*}\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>σ</mi> <mo>&gt;</mo> <mmultiscripts> <mi>p</mi> <mrow /> <mrow> <mrow /> <mo>∗</mo> </mrow> </mmultiscripts> </mrow> </math></EquationSource> </InlineEquation>.</p>

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Existence and Concentration of Ground State Solutions for a Class of Subcritical, Critical or Supercritical Caffarelli-Kohn-Nirenberg Type Problems

  • Giovany M. Figueiredo,
  • George D. F. L. Kiametis,
  • Abdolrahman Razani

摘要

In this paper, we investigate the quasilinear problem given by the following equation in \(\mathbb {R}^{N}\) R N : \(\begin{aligned}&-\text{ div }\left( |x|^{-ap}|\nabla u|^{p-2}\nabla u\right) +|x|^{-bp^{*}}[1+\mu V(z)]|u|^{p-2}u\\ &\quad = |x|^{-bp^{*}}f(u)+|x|^{-bp^{*}}\varrho |u|^{\sigma -2}u. \end{aligned}\) - div | x | - a p | u | p - 2 u + | x | - b p [ 1 + μ V ( z ) ] | u | p - 2 u = | x | - b p f ( u ) + | x | - b p ϱ | u | σ - 2 u . Here, \(1<p<N\) 1 < p < N , \(0\le a< \frac{N-p}{p}\) 0 a < N - p p , \(a<b\le a+1\) a < b a + 1 , \(p=p(a,b)=\frac{pN}{N-dp}\) p = p ( a , b ) = pN N - d p and \(d=1+a-b\) d = 1 + a - b . This equation exhibits singularity not only in the nonlinearity but also in the operator. By imposing suitable assumptions on the functions V and f, we establish the existence of solutions and investigate their concentration behavior as \(\mu \rightarrow +\infty \) μ + . We consider three cases: the subcritical case, the critical case, and the supercritical case. In the subcritical case, we have \(\varrho =0\) ϱ = 0 , while in the critical case, we have \(\varrho =1\) ϱ = 1 and \(\sigma =p^{*}\) σ = p . In the supercritical case, we have \(\varrho =1\) ϱ = 1 and \(\sigma >p^{*}\) σ > p .