<p>Let <InlineEquation ID="IEq3"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="13_2025_2119_Article_IEq3.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="72" /> </InlineMediaObject> <EquationSource Format="TEX">\(\beta \in (0,n)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>β</mi> <mo>∈</mo> <mo stretchy="false">(</mo> <mn>0</mn> <mo>,</mo> <mi>n</mi> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation>. In this paper, we study the boundedness of the Calderón–Zygmund type singular integral <Equation ID="Equ34"> <MediaObject> <ImageObject Color="BlackWhite" FileRef="13_2025_2119_Article_Equ34.gif" Format="GIF" Height="52" Rendition="HTML" Resolution="72" Type="Linedraw" Width="262" /> </MediaObject> <EquationSource Format="TEX">\( T(f)(x):=\mathrm {p.v.}\int \limits _{\mathbb {R}^n}\frac{\Omega (y)}{|y|^{n-\beta }}f(x-y)\,dy \)</EquationSource> <EquationSource Format="MATHML"><math display="block"> <mrow> <mi>T</mi> <mrow> <mo stretchy="false">(</mo> <mi>f</mi> <mo stretchy="false">)</mo> </mrow> <mrow> <mo stretchy="false">(</mo> <mi>x</mi> <mo stretchy="false">)</mo> </mrow> <mo>:</mo> <mo>=</mo> <mrow> <mi mathvariant="normal">p</mi> <mo>.</mo> <mi mathvariant="normal">v</mi> <mo>.</mo> </mrow> <munder> <mo movablelimits="false">∫</mo> <msup> <mrow> <mi mathvariant="double-struck">R</mi> </mrow> <mi>n</mi> </msup> </munder> <mfrac> <mrow> <mi mathvariant="normal">Ω</mi> <mo stretchy="false">(</mo> <mi>y</mi> <mo stretchy="false">)</mo> </mrow> <msup> <mrow> <mo stretchy="false">|</mo> <mi>y</mi> <mo stretchy="false">|</mo> </mrow> <mrow> <mi>n</mi> <mo>-</mo> <mi>β</mi> </mrow> </msup> </mfrac> <mi>f</mi> <mrow> <mo stretchy="false">(</mo> <mi>x</mi> <mo>-</mo> <mi>y</mi> <mo stretchy="false">)</mo> </mrow> <mspace width="0.166667em" /> <mi>d</mi> <mi>y</mi> </mrow> </math></EquationSource> </Equation>on the space <InlineEquation ID="IEq4"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="13_2025_2119_Article_IEq4.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="71" /> </InlineMediaObject> <EquationSource Format="TEX">\(\textrm{BMO}(\mathbb {R}^n)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mtext>BMO</mtext> <mo stretchy="false">(</mo> <msup> <mrow> <mi mathvariant="double-struck">R</mi> </mrow> <mi>n</mi> </msup> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation>. Precisely, let <InlineEquation ID="IEq5"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="13_2025_2119_Article_IEq5.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="77" /> </InlineMediaObject> <EquationSource Format="TEX">\(q\in (1,\infty )\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>q</mi> <mo>∈</mo> <mo stretchy="false">(</mo> <mn>1</mn> <mo>,</mo> <mi>∞</mi> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation> and <InlineEquation ID="IEq6"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="13_2025_2119_Article_IEq6.gif" Format="GIF" Height="27" Rendition="HTML" Resolution="72" Type="Linedraw" Width="101" /> </InlineMediaObject> <EquationSource Format="TEX">\(\beta \in (0,\frac{(q-1)n}{q})\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>β</mi> <mo>∈</mo> <mo stretchy="false">(</mo> <mn>0</mn> <mo>,</mo> <mfrac> <mrow> <mo stretchy="false">(</mo> <mi>q</mi> <mo>-</mo> <mn>1</mn> <mo stretchy="false">)</mo> <mi>n</mi> </mrow> <mi>q</mi> </mfrac> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation>. We prove that, for any <InlineEquation ID="IEq7"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="13_2025_2119_Article_IEq7.gif" Format="GIF" Height="22" Rendition="HTML" Resolution="72" Type="Linedraw" Width="173" /> </InlineMediaObject> <EquationSource Format="TEX">\(f\in \textrm{BMO}(\mathbb {R}^n)\cap L^{q'}(\mathbb {R}^n)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>f</mi> <mo>∈</mo> <mtext>BMO</mtext> <mrow> <mo stretchy="false">(</mo> <msup> <mrow> <mi mathvariant="double-struck">R</mi> </mrow> <mi>n</mi> </msup> <mo stretchy="false">)</mo> </mrow> <mo>∩</mo> <msup> <mi>L</mi> <msup> <mi>q</mi> <mo>′</mo> </msup> </msup> <mrow> <mo stretchy="false">(</mo> <msup> <mrow> <mi mathvariant="double-struck">R</mi> </mrow> <mi>n</mi> </msup> <mo stretchy="false">)</mo> </mrow> </mrow> </math></EquationSource> </InlineEquation>, <InlineEquation ID="IEq8"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="13_2025_2119_Article_IEq8.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="114" /> </InlineMediaObject> <EquationSource Format="TEX">\(Tf\in \textrm{BMO}(\mathbb {R}^n)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>T</mi> <mi>f</mi> <mo>∈</mo> <mtext>BMO</mtext> <mo stretchy="false">(</mo> <msup> <mrow> <mi mathvariant="double-struck">R</mi> </mrow> <mi>n</mi> </msup> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation> and <Equation ID="Equ35"> <MediaObject> <ImageObject Color="BlackWhite" FileRef="13_2025_2119_Article_Equ35.gif" Format="GIF" Height="64" Rendition="HTML" Resolution="72" Type="Linedraw" Width="449" /> </MediaObject> <EquationSource Format="TEX">\( \Vert Tf\Vert _{\textrm{BMO}(\mathbb {R}^n)}\le C\left[ \Vert f\Vert _{\textrm{BMO}(\mathbb {R}^n)}+\frac{\beta ^{\frac{(q-1)n}{q}}}{\root q \of {n(q-1)-\beta q}}\Vert f\Vert _{L^{q'}(\mathbb {R}^n)}\right] , \)</EquationSource> <EquationSource Format="MATHML"><math display="block"> <mrow> <msub> <mrow> <mo stretchy="false">‖</mo> <mi>T</mi> <mi>f</mi> <mo stretchy="false">‖</mo> </mrow> <mrow> <mtext>BMO</mtext> <mo stretchy="false">(</mo> <msup> <mrow> <mi mathvariant="double-struck">R</mi> </mrow> <mi>n</mi> </msup> <mo stretchy="false">)</mo> </mrow> </msub> <mo>≤</mo> <mi>C</mi> <mfenced close="]" open="["> <msub> <mrow> <mo stretchy="false">‖</mo> <mi>f</mi> <mo stretchy="false">‖</mo> </mrow> <mrow> <mtext>BMO</mtext> <mo stretchy="false">(</mo> <msup> <mrow> <mi mathvariant="double-struck">R</mi> </mrow> <mi>n</mi> </msup> <mo stretchy="false">)</mo> </mrow> </msub> <mo>+</mo> <mfrac> <msup> <mi>β</mi> <mfrac> <mrow> <mo stretchy="false">(</mo> <mi>q</mi> <mo>-</mo> <mn>1</mn> <mo stretchy="false">)</mo> <mi>n</mi> </mrow> <mi>q</mi> </mfrac> </msup> <mroot> <mrow> <mi>n</mi> <mo stretchy="false">(</mo> <mi>q</mi> <mo>-</mo> <mn>1</mn> <mo stretchy="false">)</mo> <mo>-</mo> <mi>β</mi> <mi>q</mi> </mrow> <mi>q</mi> </mroot> </mfrac> <msub> <mrow> <mo stretchy="false">‖</mo> <mi>f</mi> <mo stretchy="false">‖</mo> </mrow> <mrow> <msup> <mi>L</mi> <msup> <mi>q</mi> <mo>′</mo> </msup> </msup> <mrow> <mo stretchy="false">(</mo> <msup> <mrow> <mi mathvariant="double-struck">R</mi> </mrow> <mi>n</mi> </msup> <mo stretchy="false">)</mo> </mrow> </mrow> </msub> </mfenced> <mo>,</mo> </mrow> </math></EquationSource> </Equation>where <InlineEquation ID="IEq9"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="13_2025_2119_Article_IEq9.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="81" /> </InlineMediaObject> <EquationSource Format="TEX">\(q'\in (1,\infty )\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <msup> <mi>q</mi> <mo>′</mo> </msup> <mo>∈</mo> <mrow> <mo stretchy="false">(</mo> <mn>1</mn> <mo>,</mo> <mi>∞</mi> <mo stretchy="false">)</mo> </mrow> </mrow> </math></EquationSource> </InlineEquation> is given by <InlineEquation ID="IEq10"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="13_2025_2119_Article_IEq10.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="104" /> </InlineMediaObject> <EquationSource Format="TEX">\(1/q+1/q'=1\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mn>1</mn> <mo stretchy="false">/</mo> <mi>q</mi> <mo>+</mo> <mn>1</mn> <mo stretchy="false">/</mo> <msup> <mi>q</mi> <mo>′</mo> </msup> <mo>=</mo> <mn>1</mn> </mrow> </math></EquationSource> </InlineEquation> and <i>C</i> is a positive constant independent of <InlineEquation ID="IEq11"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="13_2025_2119_Article_IEq11.gif" Format="GIF" Height="17" Rendition="HTML" Resolution="72" Type="Linedraw" Width="15" /> </InlineMediaObject> <EquationSource Format="TEX">\(\beta \)</EquationSource> <EquationSource Format="MATHML"><math> <mi>β</mi> </math></EquationSource> </InlineEquation> and <i>f</i>. This estimate can be seen as a further development for the corresponding results in the scale of Lebesgue spaces, established by Chen and Guo (J Funct Anal 281:Paper No. 109196, 2021), in the endpoint case.</p>

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Boundedness estimate for certain Calderón–Zygmund type singular integrals on \(\textrm{BMO}\) spaces

  • Yinping Xin,
  • Sibei Yang

摘要

Let \(\beta \in (0,n)\) β ( 0 , n ) . In this paper, we study the boundedness of the Calderón–Zygmund type singular integral \( T(f)(x):=\mathrm {p.v.}\int \limits _{\mathbb {R}^n}\frac{\Omega (y)}{|y|^{n-\beta }}f(x-y)\,dy \) T ( f ) ( x ) : = p . v . R n Ω ( y ) | y | n - β f ( x - y ) d y on the space \(\textrm{BMO}(\mathbb {R}^n)\) BMO ( R n ) . Precisely, let \(q\in (1,\infty )\) q ( 1 , ) and \(\beta \in (0,\frac{(q-1)n}{q})\) β ( 0 , ( q - 1 ) n q ) . We prove that, for any \(f\in \textrm{BMO}(\mathbb {R}^n)\cap L^{q'}(\mathbb {R}^n)\) f BMO ( R n ) L q ( R n ) , \(Tf\in \textrm{BMO}(\mathbb {R}^n)\) T f BMO ( R n ) and \( \Vert Tf\Vert _{\textrm{BMO}(\mathbb {R}^n)}\le C\left[ \Vert f\Vert _{\textrm{BMO}(\mathbb {R}^n)}+\frac{\beta ^{\frac{(q-1)n}{q}}}{\root q \of {n(q-1)-\beta q}}\Vert f\Vert _{L^{q'}(\mathbb {R}^n)}\right] , \) T f BMO ( R n ) C f BMO ( R n ) + β ( q - 1 ) n q n ( q - 1 ) - β q q f L q ( R n ) , where \(q'\in (1,\infty )\) q ( 1 , ) is given by \(1/q+1/q'=1\) 1 / q + 1 / q = 1 and C is a positive constant independent of \(\beta \) β and f. This estimate can be seen as a further development for the corresponding results in the scale of Lebesgue spaces, established by Chen and Guo (J Funct Anal 281:Paper No. 109196, 2021), in the endpoint case.