<p>Let <Equation ID="Equ30"> <EquationSource Format="TEX">\( S(j)= \sum _{\nu =1}^\infty \frac{\nu }{16^\nu (2\nu -1)^2 (2\nu +1)(2\nu +j)}{2\nu \atopwithdelims ()\nu }^2, \quad j\in \{2,3,4,... \}. \)</EquationSource> <EquationSource Format="MATHML"><math display="block"> <mrow> <mi>S</mi> <mrow> <mo stretchy="false">(</mo> <mi>j</mi> <mo stretchy="false">)</mo> </mrow> <mo>=</mo> <munderover> <mo>∑</mo> <mrow> <mi>ν</mi> <mo>=</mo> <mn>1</mn> </mrow> <mi>∞</mi> </munderover> <mfrac> <mi>ν</mi> <mrow> <msup> <mn>16</mn> <mi>ν</mi> </msup> <msup> <mrow> <mo stretchy="false">(</mo> <mn>2</mn> <mi>ν</mi> <mo>-</mo> <mn>1</mn> <mo stretchy="false">)</mo> </mrow> <mn>2</mn> </msup> <mrow> <mo stretchy="false">(</mo> <mn>2</mn> <mi>ν</mi> <mo>+</mo> <mn>1</mn> <mo stretchy="false">)</mo> </mrow> <mrow> <mo stretchy="false">(</mo> <mn>2</mn> <mi>ν</mi> <mo>+</mo> <mi>j</mi> <mo stretchy="false">)</mo> </mrow> </mrow> </mfrac> <msup> <mfenced close=")" open="("> <mfrac linethickness="0pt"> <mrow> <mn>2</mn> <mi>ν</mi> </mrow> <mi>ν</mi> </mfrac> </mfenced> <mn>2</mn> </msup> <mo>,</mo> <mspace width="1em" /> <mi>j</mi> <mo>∈</mo> <mrow> <mo stretchy="false">{</mo> <mn>2</mn> <mo>,</mo> <mn>3</mn> <mo>,</mo> <mn>4</mn> <mo>,</mo> <mo>.</mo> <mo>.</mo> <mo>.</mo> <mo stretchy="false">}</mo> </mrow> <mo>.</mo> </mrow> </math></EquationSource> </Equation>In 2022, N. Bhandari showed that for <InlineEquation ID="IEq1"> <EquationSource Format="TEX">\(j\in \{3,4,5\}\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>j</mi> <mo>∈</mo> <mo stretchy="false">{</mo> <mn>3</mn> <mo>,</mo> <mn>4</mn> <mo>,</mo> <mn>5</mn> <mo stretchy="false">}</mo> </mrow> </math></EquationSource> </InlineEquation> there are rational numbers <InlineEquation ID="IEq2"> <EquationSource Format="TEX">\(a_j\)</EquationSource> <EquationSource Format="MATHML"><math> <msub> <mi>a</mi> <mi>j</mi> </msub> </math></EquationSource> </InlineEquation> and <InlineEquation ID="IEq3"> <EquationSource Format="TEX">\(b_j\)</EquationSource> <EquationSource Format="MATHML"><math> <msub> <mi>b</mi> <mi>j</mi> </msub> </math></EquationSource> </InlineEquation> such that <Equation ID="Equ31"> <EquationSource Format="TEX">\( 4 \pi S(j)=a_j-b_ jG, \)</EquationSource> <EquationSource Format="MATHML"><math display="block"> <mrow> <mn>4</mn> <mi>π</mi> <mi>S</mi> <mrow> <mo stretchy="false">(</mo> <mi>j</mi> <mo stretchy="false">)</mo> </mrow> <mo>=</mo> <msub> <mi>a</mi> <mi>j</mi> </msub> <mo>-</mo> <msub> <mi>b</mi> <mi>j</mi> </msub> <mi>G</mi> <mo>,</mo> </mrow> </math></EquationSource> </Equation>where <i>G</i> denotes the Catalan constant. He conjectured that this representation holds for all <InlineEquation ID="IEq4"> <EquationSource Format="TEX">\(j\ge 3\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>j</mi> <mo>≥</mo> <mn>3</mn> </mrow> </math></EquationSource> </InlineEquation>. Here, we prove this conjecture. More precisely, we offer recursion formulas to determine the numbers <InlineEquation ID="IEq5"> <EquationSource Format="TEX">\(a_j\)</EquationSource> <EquationSource Format="MATHML"><math> <msub> <mi>a</mi> <mi>j</mi> </msub> </math></EquationSource> </InlineEquation> and <i>bj</i> <InlineEquation ID="IEq6"> <EquationSource Format="TEX">\((j\ge 3)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mo stretchy="false">(</mo> <mi>j</mi> <mo>≥</mo> <mn>3</mn> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation> explicitly.</p>

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A class of series representations for Catalan’s constant

  • HORST ALZER,
  • MAN KAM KWONG

摘要

Let \( S(j)= \sum _{\nu =1}^\infty \frac{\nu }{16^\nu (2\nu -1)^2 (2\nu +1)(2\nu +j)}{2\nu \atopwithdelims ()\nu }^2, \quad j\in \{2,3,4,... \}. \) S ( j ) = ν = 1 ν 16 ν ( 2 ν - 1 ) 2 ( 2 ν + 1 ) ( 2 ν + j ) 2 ν ν 2 , j { 2 , 3 , 4 , . . . } . In 2022, N. Bhandari showed that for \(j\in \{3,4,5\}\) j { 3 , 4 , 5 } there are rational numbers \(a_j\) a j and \(b_j\) b j such that \( 4 \pi S(j)=a_j-b_ jG, \) 4 π S ( j ) = a j - b j G , where G denotes the Catalan constant. He conjectured that this representation holds for all \(j\ge 3\) j 3 . Here, we prove this conjecture. More precisely, we offer recursion formulas to determine the numbers \(a_j\) a j and bj \((j\ge 3)\) ( j 3 ) explicitly.